Katex test post

Published: 14 Mar 2026

Which formula represents work (W) when force (F) moves an object over a displacement (S)?

W = F \times S

W = \frac{F}{S}

W = F + S

W = F - S

W = F \times S

Work is calculated as the product of force and displacement in the direction of the force. How is work calculated when a force is applied at an angle to the direction of motion?

W = F \times S

W = \frac{F}{S}

W = F \times S \times \cos(\theta)

W = F \times S \times \sin(\theta)

W = F \times S \times \cos(\theta)

The work done when a force is applied at an angle is calculated using the formula

W = F \times S \times \cos(\theta)

. What is the mathematical expression for gravitational potential energy?

P.E = m \times g \times h

P.E = F \times s

P.E = mv^{2}

P.E = E \times t

P.E = m \times g \times h

Gravitational potential energy is calculated using the formula

P.E = m \times g \times h

. What is the work done against the force of gravity when lifting an object?

W = F \times d

W = m \times g \times h

W = P \times t

W = KE + PE

W = m \times g \times h

When lifting an object against gravity, the work done is given by the formula

W = m \times g \times h

Which formula represents work (W) when force (F) moves an object over a displacement (S)?

W = F \times<span style="mso-spacerun:yes">  </span>S

$W = \frac{F}{S}$

W = F + S

$W = F - S$

W = F \times<span style="mso-spacerun:yes">  </span>S

Work is calculated as the product of force and displacement in the direction of the force. How is work calculated when a force is applied at an angle to the direction of motion?

W = F \times<span style="mso-spacerun:yes"> </span>S

$W = \frac{F}{S}$

W = F \times<span style="mso-spacerun:yes">  </span>S\times<span style="mso-spacerun:yes">  </span>\cos(\theta)

W = F \times<span style="mso-spacerun:yes">  </span>S\times<span style="mso-spacerun:yes">  </span>\sin(\theta)

W = F \times<span style="mso-spacerun:yes">  </span>S\times<span style="mso-spacerun:yes">  </span>\cos(\theta)

The work done when a force is applied at an angle is calculated using the formula $W = F \times S \times \cos(\theta)$ . What is the mathematical expression for gravitational potential energy?

P.E = m \times<span style="mso-spacerun:yes">  </span>g\times<span style="mso-spacerun:yes">  </span>h

P.E = F \times<span style="mso-spacerun:yes"> </span>s

$P.E = mv^{2}$

P.E = E \times<span style="mso-spacerun:yes"> </span>t

P.E = m \times<span style="mso-spacerun:yes">  </span>g\times<span style="mso-spacerun:yes">  </span>h

Gravitational potential energy is calculated using the formula $P.E = m \times g \times h$ . What is the work done against the force of gravity when lifting an object?

W = F \times<span style="mso-spacerun:yes"> </span>d

W = m \times<span style="mso-spacerun:yes">  </span>g\times<span style="mso-spacerun:yes">  </span>h

W = P \times<span style="mso-spacerun:yes"> </span>t

$W = KE + PE$

W = m \times<span style="mso-spacerun:yes">  </span>g\times<span style="mso-spacerun:yes">  </span>h

When lifting an object against gravity, the work done is given by the formula $W = m \times g \times h$ .

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This is Symbol $a^2+bx \% =-5$

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Percentage symbol % shows

\dfrac{2}{5} \times \frac{2}{5} %

This is

\dfrac{2}{5} \times \frac{2}{5} %

This is $\dfrac{2}{5} \times \frac{2}{5} %$

This is $\frac{2}{5}$

\begin{array}{l|rr} 2 & 8, & 12 \\ \hline 2 & 4, & 6 \\ \hline 2 & 2, & 3 \\ \hline 3 & 1, & 3 \\ \hline & 1, & 1 \end{array}

This is $\dfrac{2}{5} \dfrac{2}{5}$

This is $\dfrac{2}{5}$

This is $\frac{2}{5}$

This is $\frac{2}{5} \cdot \frac{2}{5}$

\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\frac{2}{5}

This is $\frac{2}{5}$